(4w)/(4w+20w^2)

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Solution for (4w)/(4w+20w^2) equation: 


D( w )

20*w^2+4*w = 0

20*w^2+4*w = 0

20*w^2+4*w = 0

20*w^2+4*w = 0

DELTA = 4^2-(0*4*20)

DELTA = 16

DELTA > 0

w = (16^(1/2)-4)/(2*20) or w = (-16^(1/2)-4)/(2*20)

w = 0 or w = -1/5

w in (-oo:-1/5) U (-1/5:0) U (0:+oo)

(4*w)/(20*w^2+4*w) = 0

20*w^2+4*w = 0

4*w*(5*w+1) = 0

5*w+1 = 0 // - 1

5*w = -1 // : 5

w = -1/5

4*w*(w+1/5) = 0

(4*w)/(4*w*(w+1/5)) = 0

4*w = 0 // : 4

w = 0

w in { 0} 

w belongs to the empty set

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